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Year 11 Maths

Arithmetic Sequences

Explore sequences with a constant common difference, learn the nth term formula, and solve real-world applications.

What Is an Arithmetic Sequence?

An arithmetic sequence (also called an arithmetic progression, or AP) is a sequence where each term is obtained by adding a constant value to the previous term. This constant is called the common difference (d).

Examples

3 7 11 15 19 ...
(d = 4)
20 17 14 11 8 ...
(d = -3)

The nth Term Formula

To find any term in an arithmetic sequence without listing all previous terms, use the nth term formula:

Tn = a + (n - 1)d

where a = first term, d = common difference, n = term number

For example, in the sequence 5, 8, 11, 14, ...: a = 5, d = 3. The 20th term is T20 = 5 + (20 - 1)(3) = 5 + 57 = 62.

Arithmetic Mean and Applications

The arithmetic mean of two numbers a and b is (a + b)/2. In a sequence, the middle term between two terms is their arithmetic mean.

Salary Increases

A starting salary of $50,000 with annual raises of $3,000 forms an AP: 50000, 53000, 56000, ...

Seating Arrangements

A theatre with 20 seats in the front row and 2 extra seats per row is an AP: 20, 22, 24, ...

Saving Plans

Saving $100 more each month than the last: $200, $300, $400, ... is an AP with d = 100.

Depreciation

An asset losing $5,000 in value each year forms a decreasing AP with d = -5000.

Key Vocabulary

Common Difference (d)

The constant value added to each term to get the next term. Found by d = Tn+1 - Tn.

First Term (a)

The starting term of the sequence, also written as T1. It anchors the entire sequence.

nth Term (Tn)

The general term formula Tn = a + (n - 1)d gives any term in the sequence directly.

Arithmetic Mean

The average of two values: (a + b)/2. The middle term between two terms in an AP.

Worked Examples

1

Find the 15th term of the sequence 2, 9, 16, 23, ...

Step 1: Identify a = 2, d = 9 - 2 = 7.

Step 2: Tn = a + (n - 1)d = 2 + (15 - 1)(7) = 2 + 98 = 100.

Answer: T15 = 100.

2

The 5th term of an AP is 23 and the 12th term is 58. Find a and d.

Step 1: T5 = a + 4d = 23 and T12 = a + 11d = 58.

Step 2: Subtract: 7d = 35, so d = 5.

Step 3: a + 4(5) = 23, so a = 23 - 20 = 3.

Answer: a = 3, d = 5. The sequence is 3, 8, 13, 18, 23, ...

3

Which term of the sequence 4, 11, 18, 25, ... is equal to 200?

Step 1: a = 4, d = 7. Set Tn = 200.

Step 2: 4 + (n - 1)(7) = 200, so 7(n - 1) = 196, giving n - 1 = 28.

Answer: n = 29. The 29th term equals 200.

Knowledge Check

Select the correct answer for each question. Click "Check Answer" to see if you are right.

Question 1

What is the common difference of the sequence 10, 7, 4, 1, -2, ...?

Question 2

Find the 10th term of the AP: 5, 11, 17, 23, ...

Question 3

The arithmetic mean of 8 and 22 is:

Question 4

If T1 = 3 and d = 5, what is Tn in terms of n?

Question 5

Is the sequence 1, 4, 9, 16, 25, ... an arithmetic sequence?

Key Concepts Summary

Optimisation Problems Geometric Sequences