Introduction to Limits
Understand the concept of a limit, learn limit notation, evaluate limits using algebraic techniques, and explore one-sided limits.
What Is a Limit?
A limit describes the value that a function approaches as the input approaches a particular value. It does not matter what happens at that point — only what happens near it.
limx→a f(x) = L
Read as: "the limit of f(x) as x approaches a equals L"
This means that as x gets closer and closer to a (from both sides), the values of f(x) get closer and closer to L.
Example: f(x) = x² − 1x − 1 as x → 1
| x | 0.9 | 0.99 | 0.999 | 1 | 1.001 | 1.01 | 1.1 |
|---|---|---|---|---|---|---|---|
| f(x) | 1.9 | 1.99 | 1.999 | undef | 2.001 | 2.01 | 2.1 |
Even though f(1) is undefined, the values approach 2 from both sides. So limx→1 f(x) = 2.
Evaluating Limits Algebraically
There are several strategies for evaluating limits:
The 0/0 Indeterminate Form
If direct substitution gives 0/0, it does NOT mean the limit is 0 or undefined. It means we need to simplify further before evaluating. This is called an indeterminate form.
One-Sided Limits
Sometimes we need to consider what happens as x approaches a value from one direction only:
limx→a− f(x)
Left-hand limit (x approaches from below)
limx→a+ f(x)
Right-hand limit (x approaches from above)
The two-sided limit limx→a f(x) exists only if both one-sided limits exist and are equal: limx→a− f(x) = limx→a+ f(x).
Key Vocabulary
Limit
The value a function approaches as the input gets closer to a specified value.
Continuous
A function is continuous at x = a if limx→a f(x) = f(a). No breaks or holes.
Indeterminate Form
An expression like 0/0 that requires further simplification to determine the limit.
One-Sided Limit
The limit as x approaches a from one direction only (left or right).
Worked Examples
Evaluate limx→3 (2x + 1).
Step 1: Try direct substitution: 2(3) + 1 = 7.
Answer: limx→3 (2x + 1) = 7.
Evaluate limx→2 x² − 4/x − 2.
Step 1: Direct substitution gives (4 − 4)/(2 − 2) = 0/0 — indeterminate.
Step 2: Factorise the numerator: x² − 4 = (x − 2)(x + 2).
Step 3: Cancel (x − 2): (x − 2)(x + 2)/x − 2 = x + 2.
Step 4: Substitute: 2 + 2 = 4.
Evaluate limx→4 √x − 2/x − 4.
Step 1: Direct substitution gives 0/0 — indeterminate.
Step 2: Multiply by the conjugate: √x − 2/x − 4 × √x + 2/√x + 2 = x − 4/(x − 4)(√x + 2)
Step 3: Cancel (x − 4): = 1/√x + 2.
Step 4: Substitute x = 4: 1/√4 + 2 = 1/4 = 0.25.
Knowledge Check
Select the correct answer for each question. Click "Check Answer" to see if you are right.
Question 1
Evaluate limx→5 (3x − 2).
Question 2
Evaluate limx→1 x² − 1/x − 1.
Question 3
What is the indeterminate form?
Question 4
For a two-sided limit to exist, what must be true?
Question 5
Evaluate limx→3 x² − 9/x − 3.
Key Concepts Summary
- ●A limit describes the value a function approaches, not necessarily its value at that point.
- ●Try direct substitution first. If you get 0/0, simplify by factorising or rationalising.
- ●The 0/0 indeterminate form does not mean the limit is zero or undefined — it means more work is needed.
- ●A two-sided limit exists only if both one-sided limits are equal.
- ●Limits are the foundation of calculus — they underpin differentiation and integration.