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Year 11 Maths

The Power Rule

Learn the shortcut for differentiating powers of x, and apply the constant multiple rule and sum/difference rule to differentiate any polynomial.

The Power Rule

The power rule is the most frequently used differentiation rule. It provides a shortcut that avoids the lengthy first-principles process for power functions.

If f(x) = xn, then

f′(x) = nxn−1

"Bring the power down, then reduce the power by 1"

Pattern Recognition

f(x) f′(x) Explanation
2x2x2−1 = 2x1 = 2x
3x²3x3−1 = 3x²
x55x45x5−1 = 5x4
x1x = x1, so 1·x0 = 1
x−1 = 1/x−x−2−1·x−2 = −1/x²
x1/2 = √x1/2x−1/21/2x−1/2 = 1/2√x

Constant Rule and Constant Multiple Rule

Constant Rule

If f(x) = c, then f′(x) = 0

The derivative of any constant is zero. A constant function has no rate of change.

Constant Multiple Rule

d/dx[c · f(x)] = c · f′(x)

Constants can be factored out of the derivative. Multiply by the constant after differentiating.

Examples:

  • d/dx [5x³] = 5 × 3x² = 15x²
  • d/dx [−2x4] = −2 × 4x³ = −8x³
  • d/dx [1/3x6] = 1/3 × 6x5 = 2x5

Sum and Difference Rule

To differentiate a sum (or difference) of functions, simply differentiate each term separately:

d/dx[f(x) ± g(x)] = f′(x) ± g′(x)

This means any polynomial can be differentiated term by term. For example:

Differentiate: y = 4x³ − 2x² + 7x − 5

dy/dx = 4(3x²) − 2(2x) + 7(1) − 0

dy/dx = 12x² − 4x + 7

Key Vocabulary

Power Rule

If f(x) = xn, then f′(x) = nxn−1. Works for any real number n.

Polynomial

A function with terms of the form axn, where n is a non-negative integer.

Differentiate

The process of finding the derivative of a function.

Gradient Function

Another name for the derivative — a function that gives the slope at each point.

Worked Examples

1

Differentiate f(x) = 6x4 − 3x² + 8.

Step 1: Apply the power rule to each term: d/dx[6x4] = 6 × 4x³ = 24x³.

Step 2: d/dx[−3x²] = −3 × 2x = −6x.

Step 3: d/dx[8] = 0 (constant rule).

Answer: f′(x) = 24x³ − 6x.

2

Find dy/dx if y = 3/x² + √x.

Step 1: Rewrite: y = 3x−2 + x1/2.

Step 2: d/dx[3x−2] = 3(−2)x−3 = −6x−3 = −6/x³.

Step 3: d/dx[x1/2] = 1/2x−1/2 = 1/2√x.

Answer: dy/dx = −6/x³ + 1/2√x

3

Find the gradient of y = x³ − 4x + 2 at x = 2.

Step 1: Differentiate: y′ = 3x² − 4.

Step 2: Substitute x = 2: y′(2) = 3(4) − 4 = 12 − 4 = 8.

Answer: The gradient at x = 2 is 8.

Knowledge Check

Select the correct answer for each question. Click "Check Answer" to see if you are right.

Question 1

Differentiate f(x) = x7.

Question 2

Differentiate y = 3x5 + 2x − 9.

Question 3

What is the derivative of a constant, e.g., f(x) = 12?

Question 4

Differentiate y = x−3.

Question 5

Find the gradient of y = 2x³ − x at the point where x = 1.

Key Concepts Summary

Year 11: First Principles Year 11: Introduction to Calculus