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Year 11 Maths

Tangent Function Graph

Explore the unique shape of the tangent graph, understand its asymptotes and period, and learn how transformations change the function.

The Basic Tangent Graph

The function y = tan x is fundamentally different from sine and cosine. Since tan x = sin xcos x, it is undefined wherever cos x = 0.

y = tan x

0π/2π3π/2

The dashed red lines show vertical asymptotes at x = π/2, 3π/2, etc.

Period = π

Unlike sin and cos (period 2π), the tangent function repeats every π units.

No Amplitude

The tangent function has no maximum or minimum value — its range is (−∞, +∞).

Asymptotes

Vertical asymptotes at x = π/2 + nπ (where n is any integer).

x-intercepts

The graph crosses the x-axis at x = nπ (where n is any integer).

Transformations of tan x

The general form of the tangent function is: y = a tan(bxc) + d

Parameter Effect Formula
aVertical stretch/compression. If negative, reflects in x-axis.Dilation factor = |a|
bChanges the period (how compressed horizontally).Period = π/|b|
cHorizontal shift (phase shift).Shift = c/b
dVertical shift; moves the centre of the graph up or down.Centre at y = d

Important: The period of the tangent function is π/|b|, not 2π/|b| like sine and cosine. The asymptotes also shift accordingly.

Finding Asymptotes

For y = tan(bxc), vertical asymptotes occur where the argument equals π/2 + nπ:

bxc = π/2 + nπ

Solve for x to find each asymptote position.

For the basic y = tan x, this gives x = π/2 + nπ, i.e., x = ..., −3π/2, −π/2, π/2, 3π/2, ...

Key Vocabulary

Asymptote

A line that a curve approaches but never touches. For tan x, these are vertical lines.

Period

The horizontal distance for one full pattern. For tan x, the period is π (not 2π).

Inflection Point

The point where the tangent curve crosses the centre line, midway between asymptotes.

Undefined

A value that does not exist. tan x is undefined when cos x = 0 (division by zero).

Worked Examples

1

Find the period and asymptotes of y = tan(2x).

Step 1: Period = π/|b| = π/2.

Step 2: Asymptotes: 2x = π/2 + nπ, so x = π/4 + nπ/2.

Answer: Period = π/2. Asymptotes at x = π/4, 3π/4, 5π/4, ...

2

Describe the transformations of y = 3 tan(x − π/6).

Step 1: a = 3: Vertical stretch by factor 3 (steeper curve).

Step 2: b = 1: Period = π/1 = π (unchanged).

Step 3: Phase shift = π/6 to the right.

Answer: Stretched vertically by 3, shifted right by π/6, period π.

3

Find the first positive asymptote of y = tan(x − π/4).

Step 1: Set the argument equal to π/2: x − π/4 = π/2.

Step 2: Solve: x = π/2 + π/4 = 3π/4.

Answer: The first positive asymptote is at x = 3π/4.

Knowledge Check

Select the correct answer for each question. Click "Check Answer" to see if you are right.

Question 1

What is the period of y = tan x?

Question 2

Where does the first positive vertical asymptote of y = tan x occur?

Question 3

What is the period of y = tan(3x)?

Question 4

What is the range of y = tan x?

Question 5

What is the value of tan(0)?

Key Concepts Summary

Year 11: Sine & Cosine Graphs Year 11: Trig Identities