Electrochemistry
Discover how chemical reactions generate electricity in galvanic cells, how electrolysis uses electricity to drive non-spontaneous reactions, and how oxidation states help track electron transfer.
Oxidation and Reduction (Redox)
Electrochemistry is built on redox reactions — reactions involving the transfer of electrons between species. Oxidation and reduction always occur together.
Oxidation
Loss of electrons (OIL — Oxidation Is Loss). The oxidation state increases.
Zn → Zn2+ + 2e−
Zinc loses 2 electrons → it is oxidised.
Reduction
Gain of electrons (RIG — Reduction Is Gain). The oxidation state decreases.
Cu2+ + 2e− → Cu
Copper ions gain 2 electrons → they are reduced.
Memory tool — OIL RIG: Oxidation Is Loss, Reduction Is Gain (of electrons).
Oxidation States
An oxidation state (or oxidation number) is a number assigned to an atom in a compound that represents the number of electrons it has gained or lost relative to its neutral state. It is a bookkeeping tool for tracking electron transfer.
Key Rules for Assigning Oxidation States:
- • Pure elements: oxidation state = 0 (e.g., Fe, O2, Cl2)
- • Monatomic ions: equals the ion charge (e.g., Na+ = +1, Cl− = −1)
- • Oxygen is usually −2 (except in peroxides: −1)
- • Hydrogen is usually +1 (except in metal hydrides: −1)
- • Sum of oxidation states in a neutral compound = 0
Example: Find oxidation state of Mn in KMnO4.
K = +1, O = −2 (four oxygens = −8). Total must = 0: +1 + Mn + (−8) = 0 → Mn = +7.
Galvanic (Voltaic) Cells
A galvanic cell converts chemical energy into electrical energy using a spontaneous redox reaction. Electrons flow from the anode (oxidation) through an external circuit to the cathode (reduction). A salt bridge completes the circuit by allowing ion flow.
Zinc-Copper Galvanic Cell
Anode (−)
Zinc electrode in ZnSO4 solution
Zn → Zn2+ + 2e−
OXIDATION occurs here
Cathode (+)
Copper electrode in CuSO4 solution
Cu2+ + 2e− → Cu
REDUCTION occurs here
Electrons flow: Zn anode → external wire → Cu cathode. Salt bridge allows ion movement.
The cell potential (voltage) measures the driving force for electron flow. It depends on the relative tendency of each half-cell to be reduced (standard reduction potentials).
Electrolysis
Electrolysis uses electrical energy to drive a non-spontaneous redox reaction. An external power source forces electrons in the opposite direction to a galvanic cell. This allows decomposition of compounds and deposition of metals.
Electrolysis of water
A direct current passes through water (with added electrolyte). Hydrogen gas forms at the cathode; oxygen forms at the anode.
2H2O → 2H2 + O2
Electroplating
A metal object is coated with a thin layer of another metal (e.g., silver, gold, chromium) by electrolysis. The object is the cathode; the plating metal is the anode. Used in jewellery, car parts, and electronics.
Industrial electrolysis — aluminium smelting
In Australia, aluminium is extracted from molten bauxite (aluminium oxide) by electrolysis in the Hall-Héroult process. Al3+ ions are reduced at the cathode to form liquid aluminium metal.
Key Vocabulary
| Term | Definition |
|---|---|
| Anode | The electrode where oxidation occurs. In a galvanic cell it is negative; in electrolysis it is connected to the positive terminal. |
| Cathode | The electrode where reduction occurs. In a galvanic cell it is positive; in electrolysis it is connected to the negative terminal. |
| Electrolyte | A substance that conducts electricity when dissolved in water or melted, due to the presence of free-moving ions. |
| Salt bridge | A device containing an electrolyte that connects the two half-cells of a galvanic cell, allowing ions to flow and maintaining electrical neutrality. |
Worked Examples
Identify what is oxidised and reduced: Mg + CuSO4 → MgSO4 + Cu
Step 1: Assign oxidation states. Mg starts at 0, becomes Mg2+ (+2). Cu2+ becomes Cu (0).
Step 2: Mg goes 0 → +2: oxidation state increases → Mg is oxidised (it is the reducing agent).
Step 3: Cu goes +2 → 0: oxidation state decreases → Cu2+ is reduced (it is the oxidising agent).
Find the oxidation state of sulfur in H2SO4.
Step 1: Assign known states: H = +1 (two H atoms = +2), O = −2 (four O atoms = −8).
Step 2: Sum must equal 0: (+2) + S + (−8) = 0.
Step 3: S = +8 − 2 = +6.
Answer: Sulfur has an oxidation state of +6 in sulfuric acid.
During electroplating of a spoon with silver, what happens at each electrode?
Cathode (spoon, connected to −): Ag+ ions from solution gain electrons and are reduced to silver metal, depositing on the spoon.
Ag+ + e− → Ag
Anode (silver bar, connected to +): Silver metal is oxidised, dissolving as Ag+ ions to replenish the solution.
Ag → Ag+ + e−
Knowledge Check
Select the correct answer for each question.
Question 1
In a redox reaction, an atom that loses electrons is said to be:
Question 2
In a galvanic cell, at which electrode does reduction occur?
Question 3
What is the oxidation state of nitrogen in NH3?
Question 4
How does electrolysis differ from a galvanic cell?
Question 5
What is the purpose of a salt bridge in a galvanic cell?
Key Concepts Summary
- •Redox reactions involve electron transfer: OIL RIG — Oxidation Is Loss, Reduction Is Gain.
- •Oxidation states are a bookkeeping tool; in neutral compounds the sum of all oxidation states equals zero.
- •A galvanic cell converts chemical energy to electrical energy via a spontaneous redox reaction.
- •Oxidation occurs at the anode; reduction occurs at the cathode (in both galvanic cells and electrolysis).
- •Electrolysis uses electrical energy to drive a non-spontaneous reaction — used in electroplating and aluminium smelting.