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Year 11 Science

Light and Electromagnetic Waves

Explore the electromagnetic spectrum, the laws of reflection and refraction, and learn to apply Snell's law to predict how light bends at boundaries between media.

The Electromagnetic Spectrum

Electromagnetic (EM) waves are transverse waves that can travel through a vacuum at the speed of light (c = 3.0 × 108 m/s). They consist of oscillating electric and magnetic fields perpendicular to each other and to the direction of travel. The EM spectrum arranges these waves by wavelength and frequency.

The Electromagnetic Spectrum

Radio

longest λ

Micro-wave

Infrared

Visible

Ultra-violet

X-rays

Gamma

shortest λ

← Increasing wavelength  |  Increasing frequency →

All EM waves travel at c = 3.0 × 108 m/s in a vacuum

Key equation: c = f × λ  Since c is constant for EM waves in a vacuum, higher frequency means shorter wavelength, and vice versa.

Reflection and Refraction

When light hits a boundary between two media, it can be reflected (bounces back), refracted (bends as it passes through) or absorbed.

Law of Reflection

The angle of incidencei) equals the angle of reflectionr). Both angles are measured from the normal (a line perpendicular to the surface).

θi = θr

Refraction

Light bends when it changes speed entering a new medium. Moving from a less dense to a more dense medium (e.g. air to glass), light bends towards the normal and slows down.

The refractive index (n) of a medium indicates how much it slows light: n = c / v.

Snell's Law: n1 sin(θ1) = n2 sin(θ2)  where n1 and n2 are the refractive indices of the two media, and θ1 and θ2 are the angles of incidence and refraction (measured from the normal).

Total Internal Reflection and Critical Angle

When light travels from a denser medium to a less dense medium (e.g. glass to air), it bends away from the normal. If the angle of incidence exceeds the critical angle, the light cannot escape and is completely reflected back inside the denser medium. This is called total internal reflection (TIR).

Finding the Critical Angle

At the critical angle, the refracted ray travels along the boundary (θ2 = 90°).

sin(θc) = n2 / n1

(where n1 > n2, i.e. light goes from denser to less dense medium)

Applications of Total Internal Reflection

Optical fibres: Light signals bounce repeatedly inside thin glass fibres, carrying data for telecommunications and medical endoscopes.

Diamonds: A high refractive index (n = 2.42) gives diamonds a small critical angle, so light reflects internally many times before emerging, creating sparkle.

Binoculars and periscopes: Prisms use TIR to redirect light paths without mirrors.

Key Vocabulary

Refractive Index (n)

A measure of how much a medium slows light. Defined as n = c / v, where c is the speed of light in a vacuum and v is the speed in the medium.

Normal

An imaginary line drawn perpendicular to a surface at the point where a ray hits. All angles in reflection and refraction are measured from the normal.

Critical Angle

The angle of incidence above which total internal reflection occurs. It only exists when light moves from a denser to a less dense medium.

Electromagnetic Spectrum

The complete range of EM waves ordered by wavelength/frequency: radio, microwave, infrared, visible, ultraviolet, X-rays, gamma rays.

Worked Examples

1

Light enters glass (n = 1.50) from air (n = 1.00) at an angle of incidence of 30°. Find the angle of refraction.

Step 1: Apply Snell's law: n1 sin(θ1) = n2 sin(θ2).

Step 2: 1.00 × sin(30°) = 1.50 × sin(θ2). So 0.500 = 1.50 × sin(θ2).

Step 3: sin(θ2) = 0.500 / 1.50 = 0.333.

Answer: θ2 = sin-1(0.333) = 19.5°. The light bends towards the normal as expected.

2

Calculate the critical angle for glass (n = 1.50) to air (n = 1.00).

Step 1: sin(θc) = n2 / n1 = 1.00 / 1.50 = 0.667.

Answer: θc = sin-1(0.667) = 41.8°. Any angle of incidence above 41.8° will produce total internal reflection.

3

An EM wave has a frequency of 5.0 × 1014 Hz. What is its wavelength and what type of EM wave is it?

Step 1: λ = c / f = (3.0 × 108) / (5.0 × 1014).

Step 2: λ = 6.0 × 10-7 m = 600 nm.

Answer: Wavelength = 600 nm, which falls in the visible light range (orange-red light).

Knowledge Check

Select the correct answer for each question. Click "Check Answer" to see if you are right.

Question 1

All electromagnetic waves travel at the same speed in:

Question 2

When light passes from air into glass, it bends:

Question 3

Total internal reflection can occur when light travels from:

Question 4

Which EM wave has the highest frequency?

Question 5

In the law of reflection, the angle of incidence is measured from:

Key Concepts Summary

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