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Year 12 Science

Electrochemistry

Understand how chemical reactions produce electricity and how electricity drives chemical reactions -- the science behind batteries, fuel cells, and electroplating.

Galvanic (Voltaic) Cells

A galvanic cell converts chemical energy into electrical energy through spontaneous redox reactions. Two different metals are placed in solutions of their ions, connected by a salt bridge and an external circuit.

Galvanic Cell Structure

Anode (−)

Oxidation occurs

e.g. Zn(s)

Zn → Zn²+ + 2e−

Salt Bridge
e− flow →

Cathode (+)

Reduction occurs

e.g. Cu(s)

Cu²+ + 2e− → Cu

Cell notation (Daniell cell): Zn(s) | Zn²+(aq) || Cu²+(aq) | Cu(s). The anode is written on the left, the cathode on the right, and || represents the salt bridge.

Remember: AN OX, RED CAT -- Anode = Oxidation, Reduction = Cathode. In a galvanic cell, electrons flow from anode to cathode through the external circuit.

Electrolytic Cells

An electrolytic cell uses electrical energy to drive a non-spontaneous redox reaction. An external power source forces electrons to flow in the opposite direction to what would occur naturally.

Galvanic Cell

  • Spontaneous reaction
  • • Produces electrical energy
  • • Anode is negative (−)
  • • Two separate solutions
  • • Has a salt bridge
  • • Example: batteries

Electrolytic Cell

  • Non-spontaneous reaction
  • • Requires electrical energy
  • • Anode is positive (+)
  • • One shared solution
  • • No salt bridge needed
  • • Example: electroplating

Applications of electrolysis: Electroplating (coating objects with metal), extraction of aluminium from bauxite (Hall-Heroult process), purification of copper, and production of chlorine gas from brine.

Standard Electrode Potentials

The standard electrode potential (E°) measures the tendency of a half-cell to be reduced. All values are measured relative to the Standard Hydrogen Electrode (SHE), which is assigned E° = 0.00 V.

Selected Standard Reduction Potentials

Half-reaction
E° (V)
Tendency
F2 + 2e− → 2F−
+2.87
Strong oxidiser
Cu²+ + 2e− → Cu
+0.34
Weak oxidiser
2H+ + 2e− → H2
0.00
Reference
Zn²+ + 2e− → Zn
-0.76
Reducing agent
Li+ + e− → Li
-3.04
Strong reducer

Calculating cell EMF:cell = E°cathode - E°anode. A positive E°cell means the reaction is spontaneous. For the Daniell cell: E° = +0.34 - (-0.76) = +1.10 V.

Predicting reactions: In a galvanic cell, the half-cell with the more negative E° is oxidised (anode), and the half-cell with the more positive E° is reduced (cathode).

Key Vocabulary

Oxidation

The loss of electrons by a species in a chemical reaction. Occurs at the anode in both galvanic and electrolytic cells.

Reduction

The gain of electrons by a species in a chemical reaction. Occurs at the cathode in both galvanic and electrolytic cells.

Salt Bridge

A device connecting two half-cells that allows ion flow to maintain electrical neutrality while preventing direct mixing of solutions.

Standard Electrode Potential (E°)

The potential of a half-cell under standard conditions (25°C, 1 mol/L, 1 atm) measured against the Standard Hydrogen Electrode.

Worked Examples

1

Calculate the standard cell potential for a cell made from Zn/Zn²+ and Cu/Cu²+ half-cells.

Step 1: Identify E° values: Zn²+/Zn = -0.76 V, Cu²+/Cu = +0.34 V.

Step 2: The more negative value (Zn) is oxidised (anode). Cu is reduced (cathode).

Step 3:cell = E°cathode - E°anode = +0.34 - (-0.76) = +1.10 V.

Answer: The standard cell potential is +1.10 V. The positive value confirms the reaction is spontaneous.

2

Write the cell notation for a galvanic cell where magnesium is oxidised and silver ions are reduced.

Step 1: Anode (oxidation): Mg(s) → Mg²+(aq) + 2e−.

Step 2: Cathode (reduction): Ag+(aq) + e− → Ag(s).

Step 3: Cell notation: anode | anode ion || cathode ion | cathode.

Answer: Mg(s) | Mg²+(aq) || Ag+(aq) | Ag(s)

3

Explain what happens at each electrode during the electrolysis of molten sodium chloride.

At the cathode (−): Na+ ions are attracted, gain electrons, and are reduced: Na+ + e− → Na(l). Liquid sodium metal forms.

At the anode (+): Cl− ions are attracted, lose electrons, and are oxidised: 2Cl− → Cl2(g) + 2e−. Chlorine gas is produced.

Overall: 2NaCl(l) → 2Na(l) + Cl2(g). This is a non-spontaneous reaction driven by the external power supply.

Knowledge Check

Select the correct answer for each question. Click "Check Answer" to see if you are right.

Question 1

In a galvanic cell, oxidation occurs at the:

Question 2

The standard cell potential for a cell with E°cathode = +0.80 V and E°anode = -0.44 V is:

Question 3

The purpose of the salt bridge in a galvanic cell is to:

Question 4

Which of the following describes an electrolytic cell?

Question 5

A half-cell with a more negative standard electrode potential will tend to be:

Key Concepts Summary

Year 12: Quantum Physics Year 12: Organic Reactions